7^2x+2=(1/49)^x+5

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Solution for 7^2x+2=(1/49)^x+5 equation: 



7^2x+2=(1/49)^x+5

We move all terms to the left:

7^2x+2-((1/49)^x+5)=0



Domain of the equation: 49)^x+5)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

7^2x-((+1/49)^x+5)+2=0

We multiply all the terms by the denominator


7^2x*49)^x+5)-((+2*49)^x+5)+1=0

We add all the numbers together, and all the variables

7^2x*49)^x+5)-(98^x+5)+1=0

Wy multiply elements

343x^3=0

We do not support expression: x^3

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